A. Next Round

time limit per test

3 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

"Contestant who earns a score equal to or greater than the k-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.

A total of n participants took part in the contest (n ≥ k), and you already know their scores. Calculate how many participants will advance to the next round.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 50) separated by a single space.

The second line contains n space-separated integers a₁, a₂, ..., a_n (0 ≤ a_i ≤ 100), where a_i is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is, for all i from 1 to n - 1 the following condition is fulfilled: a_i ≥ a_i + 1).

Output

Output the number of participants who advance to the next round.

Sample test(s)

Input

8 5 10 9 8 7 7 7 5 5

Output

6

Input

4 2 0 0 0 0

Output

0

Note

In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.

In the second example nobody got a positive score.

 

 

 

 

很简单的题目~~~~~

#include
      
        int mm[120]; int main() {
    int n,k; while(scanf("%d%d",&n,&k)!=EOF)     {
    for(int i=1;i<=n;i++)           scanf("%d",&mm[i]); int res=k; if(mm[k]>0)         {
    for(int i=k+1;i<=n;i++)             {
    if(mm[i]
       
        =1;i--)             {
    if(mm[i]>0) break;                 res--;             }            }         printf("%d\n",res);         }    return 0; }